-147=3x^2-42x

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Solution for -147=3x^2-42x equation: 



-147=3x^2-42x

We move all terms to the left:

-147-(3x^2-42x)=0

We get rid of parentheses

-3x^2+42x-147=0

a = -3; b = 42; c = -147;
Δ = b2-4ac
Δ = 422-4·(-3)·(-147)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-42}{-6}=+7$

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